What Is The Minimum Resultant Possible When Adding A 3-unit Vector To An 8-unit Vector?a. 24b. 11c. 8d. (2024)

Physics High School

Answers

Answer 1

The minimum resultant is possible when adding a 3-unit vector to an 8-unit vector is 5 (option d).

To understand this, we need to consider vector addition and the concept of the angle between the vectors. When two vectors are added, their magnitudes and directions matter. The minimum resultant occurs when the two vectors are arranged in a straight line but point in opposite directions (i.e., when the angle between them is 180 degrees).

In this case, the 8-unit vector and the 3-unit vector are aligned such that they are working against each other, effectively subtracting their magnitudes. Mathematically, this can be represented as:

Minimum resultant = |8 - 3| = 5

The minimum possible resultant for these vectors is 5 units. Therefore the correct option is D

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Related Questions

A jogger runs 300m due west and then turns and runs 500m due south. what is her total displacement

Answers

Answer:

The answer for his displacement is 583m,S59°W

Explanation:

hyp²=opp²+adj²

x²=300²+500²

x²=340000

take square root of both sides

x≈583

using SOH CAH TOA

tany=opp/adj

tany=500/300

y=tan‐¹(5/3)

y≈59°

A horse accelerates uniformly from 0 to 20 mi/h in 2 seconds. What is the acceleration?A. 10 mi*h-1B. 10 mi*-2C. 10 mih-1s-1D. 10 mi*h-2

Answers

The correct answer is C. 10 mi/h/s or 10 mih-1s-1. To find the acceleration of the horse, you can use the formula: acceleration = (final velocity - initial velocity) / time taken.

In this case, the initial velocity is 0 mi/h, the final velocity is 20 mi/h, and the time taken is 2 seconds.

Acceleration is defined as the rate of change of velocity over time. In this case, the initial velocity is 0 and the final velocity is 20 mi/h, and the time taken is 2 seconds.

So, we can use the formula:

acceleration = (final velocity - initial velocity) / time taken
acceleration = (20 mi/h - 0 mi/h) / 2 s = 20 mi/h / 2 s = 10 mi/h/s
acceleration = (20 mi/h - 0) / 2 seconds
acceleration = 10 mi*h-2

Therefore, the acceleration of the horse is 10 mi*h-2.

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In work, the collisions of molecules are ______, while those in heat are ______a) random, random b) directional, random c) random, directional d) directional,directional

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The collisions of molecules are directional, while those in heat are random.

In work, the collisions of molecules are directional, while those in heat are random. The Latin "moles," or little unit of mass, is the source of the term "molecule," according to Merriam-Webster and the Online Etymology Dictionary.

The word is taken from the French molécule (1678), which was itself derived from the diminutive of the Latin word moles, meaning "mass, barrier" in New Latin.

Therefore, the correct option is b) directional, random.

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_____ depend on how the current state of a system was reacheda) State functionsb) Temperature c) Pressure d) Volume

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Option a) State functions. State functions are properties of a system that only depend on the current state of the system and not on how the system reached that state.

State functions do not depend on the path taken to reach a particular state, but only on the final and initial states themselves.

Temperature, pressure, and volume are not state functions as they can be influenced by external factors and their values can change depending on the process or path taken to reach a particular state.

The dependence of a system on how it reached a particular state is determined by whether the property is a state function or not.

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the process of reabsorption describes the process of passing materials between the ___ and the ____ .

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The process of reabsorption describes the process of passing materials between the renal tubules and the bloodstream.

This process occurs in the kidneys, where waste products are filtered out of the blood and sent to the bladder to be excreted as urine. As the filtered fluid travels through the renal tubules, important nutrients and electrolytes are reabsorbed back into the bloodstream to maintain the body's homeostasis.

This includes substances such as glucose, amino acids, sodium, and water. The reabsorption process is facilitated by specialized cells in the renal tubules that actively transport these substances back into the bloodstream. However, not all substances are reabsorbed, and some are excreted in the urine.

The process of reabsorption is crucial in maintaining proper fluid balance and preventing dehydration, as well as regulating blood pressure and pH levels in the body.

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hototransistors allow more current to pass through the circuit in the presence of a brighter light source. if there is a single resistor in series with a phototransistor, does this mean that a brighter light source would result in a larger or smaller voltage drop across the resistor? explain.

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A brighter light source will result in a larger voltage drop across the resistor in a circuit with a phototransistor because the increased current flowing through the circuit causes a larger voltage drop according to Ohm's law.

If there is a single resistor in series with a phototransistor, a brighter light source would result in a larger voltage drop across the resistor.

The reason for this is that when the phototransistor is exposed to a brighter light source, more current will flow through the circuit because the phototransistor allows more current to pass through in the presence of a brighter light.

This increased current will cause a larger voltage drop across the resistor because the voltage drop across a resistor is directly proportional to the current flowing through it according to Ohm's law.

Ohm's law states that the voltage drop (V) across a resistor is equal to the current (I) flowing through it multiplied by the resistance (R) of the resistor:

V = IR.

Therefore, if the current through the circuit increases due to the brighter light source, the voltage drop across the resistor will also increase because the resistance of the resistor remains constant.

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what is looping? select one: a. the process of combining different sound tracks into a single track b. the rerecording of sound first recorded on set c. the recording of sound on set d. the process of converting sound waves into electrical signals

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Looping refers to option B, which is the process of rerecording sound that was originally recorded on set. This is done in a studio setting and is also known as Automated Dialogue Replacement (ADR).

It is typically used to fix any issues with the original sound recording, such as background noise or actors speaking too softly or too loudly. By rerecording the dialogue in a controlled environment, the sound can be adjusted to better fit the scene and create a more polished final product.

Definitions of looping. (computer science) executing the same set of instructions a given number of times or until a specified result is obtained. synonyms: iteration. type of: physical process, process. a sustained phenomenon or one marked by gradual changes through a series of states.

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an aluminum loop lies flat on a horizontal surface. a bar magnet is held above the center of the loop with its south pole closest to the loop. if the magnet is moved closer to the loop from this position, what is the direction of the induced current in the loop, as viewed from above as the magnet is moving?

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As the bar magnet is moved closer to the aluminum loop, a magnetic field is induced in the loop. The direction of the induced current in the loop, as viewed from above as the magnet is moving, would be counterclockwise. This is because the magnetic field of the bar magnet is changing.

And according to Faraday's Law of Electromagnetic Induction, this change induces an electric current in the loop that flows in a direction to create a magnetic field that opposes the change. In this case, the counterclockwise current creates a magnetic field that opposes the approach of the south pole of the magnet.

A bar magnet is a type of magnet that has a long, straight shape with a north pole at one end and a south pole at the other. Bar magnets can be made from materials that have ferromagnetic properties, such as iron, nickel, or cobalt.

When a bar magnet is suspended or placed on a pivot point, it will align itself in a north-south direction due to the Earth's magnetic field. This property of bar magnets is used in compasses to indicate the direction of north.

The magnetic field of a bar magnet is strongest at its poles, where the magnetic field lines converge, and weakest in the middle. The strength of the magnetic field is proportional to the magnet's magnetic moment, which is determined by the magnet's size, shape, and the magnetic properties of the material it's made from.

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(True or False) If I have a spherical charge distribution with a non-uniform volume charge density rho=r^2cos(theta), I can use Gauss's Law and its symmetry arguments to find the electric field E due to it anywhere in space.

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False. The main answer is that you cannot use Gauss's Law to find the electric field due to a non-uniform charge distribution, even if it is spherically symmetric.

This is because Gauss's Law only applies to cases with sufficient symmetry, such as uniform charge densities or point charges. The explanation is that Gauss's Law relies on the fact that the electric flux through a closed surface is proportional to the enclosed charge, but with non-uniform charge densities, this proportionality breaks down. Therefore, one must use other methods, such as integrating over the volume of the charge distribution, to find the electric field. In conclusion, while Gauss's Law is a powerful tool for calculating electric fields in certain situations, it is not universally applicable and must be used with caution.

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a virtual image is formed 20.5 cm from a concave mirror having a radius of curvature of 41.5 cm. (a) find the position of the object. cm in front of the mirror (b) what is the magnification of the mirror?

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The magnification of the mirror after calculations is 0.99.

We can use the mirror formula and magnification formula to solve this problem:

1/f =[tex]1/d_o + 1/d_i[/tex]

magnification = -[tex]d_i/d_o[/tex]

where f is the focal length of the mirror, [tex]d_o[/tex] is the distance of the object from the mirror, and [tex]d_i[/tex] is the distance of the image from the mirror.

(a) To find the position of the object, we can rearrange the mirror formula:

[tex]1/d_o = 1/f - 1/d_i[/tex]

Substituting the given values, we get:

[tex]1/d_o[/tex] = 1/(-41.5 cm/2) - 1/20.5 cm

Simplifying, we get:

[tex]1/d_o[/tex] = -0.0482 cm^-1

Therefore:

[tex]d_o[/tex] = -20.7 cm

Note that the negative sign indicates that the object is located in front of the mirror.

Therefore, the object is located 20.7 cm in front of the mirror.

(b) To find the magnification, we can use the magnification formula:

magnification = -[tex]d_i/d_o[/tex]

Substituting the calculated values, we get:

magnification = -20.5 cm / (-20.7 cm)

Simplifying, we get:

magnification = 0.99

Therefore, the magnification of the mirror is 0.99.

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Q: How do fuses work? Why are they necessary?

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Fuses are electrical safety devices that protect electrical circuits from overloading or short-circuiting.

They work by interrupting the flow of electrical current when it exceeds a safe level, which prevents damage to the circuit and the connected devices.

Fuses contain a metal wire or filament that melts when the current becomes too high, breaking the circuit and stopping the flow of electricity. This protects the circuit from damage and prevents fires or other hazards.

Fuses are necessary because they provide a crucial layer of protection for electrical systems, ensuring that they operate safely and reliably. Without fuses, electrical circuits could overload or short-circuit, leading to costly and dangerous damage.

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the nucleus of our Galaxy (which may be elongated and not spherical) generates

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The elongated nucleus of our galaxy is responsible for generating a wide range of phenomena, including the influence of a supermassive black hole, star formation activity, and the production of synchrotron radiation. These processes are vital to understanding the overall structure, dynamics, and evolution of the Milky Way.

The nucleus of our galaxy, also known as the galactic center, is a region that plays a crucial role in generating various phenomena. Located approximately 26,000 light-years from Earth, it is thought to have an elongated shape rather than being perfectly spherical.

At the heart of the galactic nucleus lies a supermassive black hole called Sagittarius A* (Sgr A*). This black hole is responsible for generating intense gravitational forces, which influence the motion and behavior of surrounding stars, gas, and dust. Additionally, Sgr A* is a major source of X-ray and radio emissions, contributing to the overall energy output of the galaxy's core.

The galactic center also exhibits a high degree of star formation activity. Massive, young stars in this region emit intense ultraviolet radiation, which in turn ionizes the surrounding gas clouds. This process leads to the creation of H II regions, which are areas of glowing ionized gas. These regions not only serve as stellar nurseries but also contribute to the overall appearance and structure of the galactic nucleus.

Furthermore, the interaction of energetic particles, magnetic fields, and turbulent gas flows in the galactic nucleus generates synchrotron radiation, which is emitted at various wavelengths, including radio, infrared, and X-ray. This radiation is an important tool for astronomers to study the complex processes occurring within the core of our galaxy.

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Modern MRI machines use electricity to generate their magnetic fields inside a circular chamber instead of using permanent magnets. Which of the following would NOT increase the strength of the MRI field?
A. Increased radius of the MRI chamber
B. Increased power supplied to the MRI machineC. Decreased resistance of the MRI machine
D. Increased current through the MRI machine

Answers

The answer is A. Increasing the radius of the MRI chamber would not increase the strength of the MRI field. The magnetic field strength in an MRI machine is directly proportional to the current passing through the coils and the number of coils present in the machine.

Hence, increasing the power supplied to the MRI machine or increasing the current passing through the machine would increase the strength of the MRI field. Decreasing the resistance of the machine would also increase the current passing through it, leading to an increase in the MRI field strength. However, increasing the radius of the MRI chamber would not have any impact on the strength of the MRI field as the magnetic field is generated by the current passing through the coils, which are located within the chamber.

Thus, the answer is A, an increased radius of the MRI chamber would not increase the strength of the MRI field.

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Why are materials liquids at higher temperatures in terms of Gibbs free energy

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The reason why materials become liquids at higher temperatures can be explained in terms of Gibbs free energy.

At higher temperatures, the entropy or disorder of the material increases, which leads to a decrease in Gibbs free energy. In other words, the system becomes more energetically favorable in the liquid state than in the solid state, resulting in a phase transition from solid to liquid. This is due to the fact that in the liquid state, the molecules have more freedom of movement and can occupy a greater number of microstates, which leads to an increase in entropy and a decrease in Gibbs free energy. Therefore, as the temperature increases, the Gibbs free energy of the liquid state becomes lower than that of the solid state, resulting in a phase transition from solid to liquid.

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a strong motor is spinning to produce 5000w of power. however, the machine tends to break after running for 120s. How many J of work is it producing?

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The fundamental SI unit of energy is called a joule, or J. One joule is equal to one kgm2s2, or the kinetic energy of a kilogram mass travelling at one meter per second.

Thus, A tennis ball moving at a speed of 6 meters per second has kinetic energy of 1 joule. A joule is the energy required to lift a medium tomato one meter in height or the energy released when that tomato is dropped from that height.

The system bears James Prescott Joule's name. The symbol's first letter (J instead of j) is uppercase since it is named after a person. However, the term is capitalized when it is written out.

The electricity required to power a 1 W LED for one second is measured in joules.

Thus, The fundamental SI unit of energy is called a joule, or J. One joule is equal to one kgm2s2, or the kinetic energy of a kilogram mass travelling at one meter per second.

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which of the following occurs when the temperature of a contained gas is reduced at constant pressure?

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When the temperature of a contained gas is reduced at constant pressure, the volume of the gas decreases according to Charles's Law.

Charles's Law states that the volume of a gas is directly proportional to its temperature when the pressure is kept constant. When the temperature of a contained gas is reduced, the gas particles lose kinetic energy, and the average speed of the particles decreases.

As a result, the gas particles do not collide with the container walls as forcefully or frequently. This leads to a decrease in the volume of the gas as it occupies less space in the container.

To summarize, when the temperature of a contained gas is reduced at constant pressure, the volume of the gas decreases due to the decreased kinetic energy and movement of the gas particles, as explained by Charles's Law.

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A 14-kg block rests on a level frictionless surface and is attached by a light string to a 5.0-kg hanging mass where the string passes over a massless frictionless pulley. If g = 9.8 m/s2, what is the tension in the connecting string?A. 2.6 NB. 21 NC. 49 ND. 36 NE. 190 N

Answers

The tension in the connecting string is 36 N (option D).

1. First, we need to determine the acceleration of the system. Since there is no friction acting on the 14-kg block, the only force acting on the system is the gravitational force acting on the 5.0-kg hanging mass.

2. To find the acceleration, we can use Newton's second law: F = ma. The force acting on the system is the gravitational force on the 5.0-kg mass (F = mg), so:
F = (5.0 kg)(9.8 m/s²) = 49 N.

3. The total mass of the system is the sum of the 14-kg and the 5.0-kg masses, which is 19 kg. Now we can find the acceleration (a) using the formula F = ma:
49 N = (19 kg)(a)
a = 49 N / 19 kg = 2.579 m/s².

4. Next, we need to determine the tension in the connecting string (T). We can analyze the forces acting on the 5.0-kg hanging mass: tension (T) and the gravitational force (mg = 5.0 kg * 9.8 m/s² = 49 N).

5. Using Newton's second law for the 5.0-kg hanging mass (F = ma), we can write:
T - mg = ma
T - (5.0 kg)(9.8 m/s²) = (5.0 kg)(2.579 m/s²)
T = (5.0 kg)(2.579 m/s²) + (5.0 kg)(9.8 m/s²)
T = 36 N.

The tension in the connecting string is 36 N.

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A hollow rubber ball, whose volume is 3 x 10-3m3 and has a mass of 1.0 kg) is held by a 1-meter-long string attached to the bottom of a large container of water. What is the tension in the string?A. 20 NB. 35 NC. 40 ND. 45 N

Answers

The closest answer to this value is A. 20 N, which is the tension in the string.

To determine the tension in the string, we need to consider two forces acting on the ball: the buoyant force and the gravitational force.

First, let's calculate the buoyant force (Fb):
Fb = V * ρ * g
where V is the volume of the ball (3 x 10⁻³ m³), ρ is the density of water (1000 kg/m³), and g is the acceleration due to gravity (9.81 m/s²).

Fb = (3 x 10⁻³ m³) * (1000 kg/m³) * (9.81 m/s²) = 29.43 N

Next, let's calculate the gravitational force (Fg):
Fg = m * g
where m is the mass of the ball (1.0 kg) and g is the acceleration due to gravity (9.81 m/s²).

Fg = (1.0 kg) * (9.81 m/s²) = 9.81 N

Now, to find the tension in the string (T), we can subtract the buoyant force from the gravitational force:
T = Fg - Fb
T = 9.81 N - 29.43 N
T = -19.62 N

Since tension cannot be negative, we take the absolute value:
T = 19.62 N

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Doug hits a hockey puck, giving it an initial velocity of 6.0 m/s. If the coefficient of kinetic friction between ice and puck is 0.20, how far will the puck slide before stopping?A. 14 mB. 19 mC. 9 mD. 11 mE. ​24 m

Answers

Answer:

KE = 1/2 M v^2 initial KE

Wf = μ M g S work done by friction in stopping puck

1/2 v^2 = μ g S

S = v^2 / (2 μ g) = 6^2 / (2 * .2 * 9.8) = 9.2 m

(C) is correct

How does cosmic inflation of the early Universe solve the flatness problem?

Answers

Cosmic inflation is a theory that explains the large-scale structure of the universe and its overall hom*ogeneity. It is believed that the universe underwent a period of rapid expansion just after the Big Bang, which is known as cosmic inflation. This period of expansion solved many of the problems that were present in the standard Big Bang model.

One of the problems that cosmic inflation solved was the flatness problem. The flatness problem refers to the observation that the universe appears to be very close to flat, meaning that it has a curvature close to zero. This is in contrast to what we would expect from the standard Big Bang model, which predicts that the universe would either be highly curved or highly open.

Cosmic inflation solved the flatness problem by causing the universe to expand so rapidly that any curvature that was present in the early universe was stretched out to an almost flat state. This means that the curvature of the universe today is very close to zero, which is consistent with observations.

Overall, cosmic inflation is an important theory in modern cosmology because it explains many of the observations that we have made about the universe, including the flatness problem.

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How much work is required to move a +150 μC point charge from P to Q?A) 0.023 JB) 0.056 JC) 75 JD) 140 JE) 2800 J

Answers

The work required to move the +150 μC point charge from P to Q is 1.35J

The answer is not listed in the given options.

The work required to move a point charge from one point to another is given by the equation:
W = q * V
where W is the work done,

q is the charge being moved,

and V is the potential difference between the two points.
To solve this problem, we need to first find the potential difference between points P and Q.

This can be done using the equation:
V = k * (Q / r).
where V is the potential difference,

k is Coulomb's constant (9 x 10^9 N*m^2/C^2),

Q is the charge causing the potential,

and r is the distance between the two points.
In this case, we have:
Q = +150 μC [tex]= 150 * 10^-6 C[/tex]
r = 0.15 m (assuming the points are a distance of 15 cm apart)
[tex]k = 9 * 10^9 N*m^2/C^2[/tex]
Plugging these values into the equation gives:
[tex]V = (9 * 10^9 N*m^2/C^2) * (150 * 10^-6 C / 0.15 m)[/tex]

= 9000 V
Now we can use the equation for work to find the amount of work required to move the point charge from P to Q:
[tex]W = (150 * 10^-6 C) * (9000 V) = 1.35 J[/tex].

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Question: How much work is required to move a +150 μC point charge from P to Q?A) 0.023 JB) 0.056 JC) 75 JD) 140 JE) 2800 J

how far should the front of the camera be from her friend?express your answer to two significant figures and include the appropriate units.express your answer to two significant figures and include the appropriate units.-long pinhole camera for a science fair project. she wants to photograph her 160-cm -tall friend and have the image on the film be 5.4 cm high.

Answers

The front of the camera should be approximately 29 cm away from her friend.

To find how far the front of the camera should be from her friend, you can use the proportion method. Since the height of the friend is 160 cm and the height of the image on the film is 5.4 cm, you can set up a proportion:

Friend's height / Image height = Distance from friend / Camera distance

160 cm / 5.4 cm = Distance from friend / Camera distance

Now, solve for the Camera distance:

Camera distance = (Distance from friend * 5.4 cm) / 160 cm

Using two significant figures, the appropriate distance for the front of the camera from her friend should be approximately 29 cm.

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a 20-ton truck collides with a 1500-lb car and causes a lot of damage to the car. during the collision

Answers

Answer:

During the collision, the truck and the car experience a force exerted on them that causes their momentum to change. The magnitude of the force depends on the duration of the collision and the masses of the objects involved.

To analyze this collision, we can use the law of conservation of momentum, which states that the total momentum of a closed system (in this case, the truck and the car) remains constant before and after the collision, provided that no external forces act on the system.

Before the collision, the truck and the car are moving with different velocities and have different momenta. The momentum of an object is given by the product of its mass and its velocity. In this problem, we are given the mass of the truck and the weight of the car, but we need to convert the weight of the car to its mass. We can do this by dividing the weight by the acceleration due to gravity:

mass_car = weight_car / g

where g is the acceleration due to gravity (approximately 9.8 m/s^2). Substituting the given values, we get:

mass_car = 1500 lb / 2.205 lb/kg / 9.8 m/s^2 = 0.68 kg

Now we can calculate the initial momenta of the truck and the car:

p_truck = m_truck * v_truck

p_car = m_car * v_car

where p is the momentum, m is the mass, and v is the velocity.

We are not given the velocities of the truck and the car, so we cannot calculate their initial momenta. However, we are told that the truck collides with the car and causes a lot of damage to the car. This suggests that the collision is not elastic, meaning that some of the kinetic energy of the truck and the car is converted into other forms of energy, such as heat, sound, or deformation of the objects involved.

In an inelastic collision, the momentum of the system is still conserved, but the kinetic energy of the system is not conserved. The final velocities of the truck and the car after the collision depend on the masses of the objects, the initial velocities before the collision, and the degree of inelasticity of the collision.

Without more information about the collision, it is difficult to determine the final velocities or the amount of damage caused to the car.

During the collision, the 20-ton truck exerts a force on the 1500-lb car, resulting in a lot of damage to the car.

This is because the truck has significantly more mass and therefore momentum than the car, causing a much larger force upon impact. The damage sustained by the car will likely be extensive due to the force of the collision.

In physics, force is defined as mass multiplied by acceleration. In this scenario, the truck has a much larger mass than the car, which means it will also have a larger force upon impact.

The momentum of an object is defined as its mass multiplied by its velocity. Again, the truck has much more momentum than the car due to its larger mass and speed.

Therefore, during the collision, the force exerted by the truck on the car is much greater than the force exerted by the car on the truck, resulting in significant damage to the car.

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The light from these stars varies periodically because of changes in the star’s _______ (how gas blocks the passage of light through it).

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"Opacity" The opacity of the gas in the star can affect the passage of light through it, causing the light emitted by the star to vary periodically.

Essentially, when the gas in the star becomes more opaque, it blocks more light from passing through, resulting in a dimming effect.

Conversely, when the gas becomes less opaque, more light can pass through, resulting in a brightening effect.

Hence, changes in a star's opacity can cause variations in the light emitted by the star.

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91. Which one of the following actions will increase the frictional force on the block?A) increasing the contact surface areaB) decreasing the contact surface areaC) increasing the weight of the blockD) decreasing the speed of the blockE) increasing the angle made by the rope

Answers

Increasing the contact surface area will increase the frictional force on the block(A).

The frictional force between two surfaces in contact is proportional to the normal force pressing the surfaces together and the coefficient of friction between them. The normal force is the force perpendicular to the contact surfaces.

Increasing the contact surface area between the block and the surface it's resting on will increase the normal force, which in turn increases the frictional force.

This can be observed in everyday life, such as when a car's tires have more grip on the road when the surface area in contact with the road is increased by adding treads or making the tires wider. Therefore, option A is the correct answer.
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1. Complete the following information to summarize
Buntyn Brothers Murder
Brother Barry's gun fired Bullet Evidence #(s)_
Brother Bradley's gun fired Bullet Evidence #(s)_
Brother Brian's gun fired Bullet Evidence #(s)_
Brother Brandon's gun fired Bullet Evidence #(s)__
Brother Billy-Bob's gun fired Bullet Evidence # (s)_

Answers

On the Buntyn Brothers Murder case, the investigation discovered that 5 brothers were involved in the shooting. Brother Barry fired a gun which left bullet evidence, but number of bullets shot was not specified.

Brother Bradley as well fired a gun, and the bullet evidence were found by the investigation, but number of bullets was not mentioned.

Brother Brian also fired a gun that left evidence of bullet, but the number of bullets is not provided.

Brother Brandon fired a gun, but it is unclear if any bullet evidence was found.

Brother Billy-Bob as well fired a gun, but there is no information regarding the number of bullets and bullet evidence found.

What is investigation?

Investigation is the gathering of information or evidence to explore a situation or event. It involves a thorough inquiry on a problem or an issue, with the purpose of identifying its causes, getting the facts, and finding solutions or recommendations for further action.

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b. (1 pt) exactly what does a catalyst do to change the the rate of the reaction? (assume the temperature does not change.)

Answers

A catalyst increases the rate of a reaction by providing an alternative pathway with a lower activation energy.

It does not change the overall energy change or equilibrium constant of the reaction. Catalysts work by stabilizing the transition state, making it easier for reactant molecules to overcome the energy barrier and form products. This allows more successful collisions to occur, resulting in an increase in reaction rate.

Catalysts are not consumed in the reaction, so a small amount can catalyze a large amount of reactants. Overall, catalysts provide an efficient and sustainable way to increase reaction rates without increasing the energy requirements or altering the reaction equilibrium.

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which statement is true?
no need to explain also :)

Answers

Carbon moves around the atmosphere in several ways. Option A is the answer.

Effects of carbon on the atmosphere

Carbon has several effects on the atmosphere, which can have significant impacts on the Earth's climate and ecosystems. Carbon dioxide (CO2), a greenhouse gas, is released into the atmosphere through human activities such as burning of fossil fuels, and deforestation. CO2 and other greenhouse gases trap heat in the Earth's atmosphere, causing global warming and climate change.

It can lead to more frequent and severe weather events such as floods, droughts, and hurricanes. This can also cause damage to ecosystems, including coral reefs, and can lead to the extinction of some species.

Excess carbon in the atmosphere can also lead to ocean acidification, as more CO2 is absorbed into the oceans, leading to a decrease in pH levels. This can harm marine life, such as coral reefs, which are important ecosystems for many marine organisms.

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(Figure 1) shows a standing wave that is oscillating at frequency 100 Hz Part A How many antinodes will there be if the frequency is doubled to 200 Hz? Express your answer as an integer. N= 8 Soome Previous Answers ✓ Correct Part B Figure 1 of 1 If the tension in the string is increased by a factor of 4, at what frequency will the string continue to oscillate figure? Express your answer with the appropriate units. IMA th ? 1 - 400 Hz V Submit Previous Are Rest Answer X Incorrect: Try Again: 5 attempts remaining

Answers

If the frequency of a standing wave that is oscillating at 100 Hz is doubled to 200 Hz, the number of antinodes will also double.

The formula for the number of antinodes (n) in a standing wave is:
n = (L / λ) + 1
where L is the length of the medium and λ is the wavelength.

Since the frequency is doubled, the wavelength will be halved (assuming the medium remains the same). This is because the speed of sound in a medium is constant, so if the frequency is doubled, the wavelength must be halved to maintain the same speed.

So, if the original wavelength at 100 Hz was λ1, then the new wavelength at 200 Hz would be λ2 = λ1/2.

Substituting this into the formula for n, we get:
n2 = (L / λ2) + 1
= (L / (λ1/2)) + 1
= 2(L / λ1) + 1

So, the number of antinodes at 200 Hz (n2) will be twice the number of antinodes at 100 Hz (n1), plus one.

Therefore, if there are n1 antinodes at 100 Hz, there will be 2n1 + 1 antinodes at 200 Hz.

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for the diffraction pattern from a single slit, circular wavelets of the wave front passing through a single slit may interfere with each other depending on the angle that the light rays make with the horizontal line through the slit. what is the condition such that destructive minima (dark spots) appear on a screen at this angle if the slit width is and the wavelength of probing light is ?

Answers

Destructive minima (dark spots) appear on a screen for the single slit diffraction pattern when the angle of diffraction can be described by sinθ = mλ/b, where m is an integer, λ is the wavelength of the light, and b is the width of the slit.

When a wave of light passes through a single slit, it diffracts and creates a pattern on a screen. This diffraction pattern is a result of interference between the wavelets that pass through the slit.

The angle at which the destructive interference occurs is given by sinθ = mλ/b, where m is an integer representing the order of the minima, λ is the wavelength of the light, and b is the width of the slit.

At these angles, the troughs of the wavelets coincide, resulting in destructive interference and the appearance of a dark spot on the screen. The spacing between the dark spots is proportional to the wavelength of light and inversely proportional to the width of the slit.

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What Is The Minimum Resultant Possible When Adding A 3-unit Vector To An 8-unit Vector?a. 24b. 11c. 8d. (2024)
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